Question

A force of 46 N acts on a ball of 0.1 kg for 0.25 s. If the ball is initially moving at 5 m/s.A. What is the impulse of one the ball?B. What is the final momentum of the ball?

Answer 1

Given

F = 46 N

m = 0.1 kg

t = 0.25 s

v0 = 5 m/s

Explanation

A. What is the impulse of one the ball?

$\begin{gathered} I=F\Delta t \\ I=46N*0.25s \\ I=11.5\text{ kg m/s} \end{gathered}$

B. What is the final momentum of the ball?

$\begin{gathered} I=\Delta p \\ 11.5=m(v_f-v_0) \\ v_f=\frac{11.5}{m}+v_0 \\ v_f=\frac{11.5}{0.1}+5 \\ v_f=120\text{ m/s} \end{gathered}$

Final momentum

$\begin{gathered} p_f=mv_f \\ p_f=0.1*120 \\ p_f=12\text{ kg m/s} \end{gathered}$