Question

If the area of a shape is 40 in^2 with a height of 10 in, what is the basea in

Answer 1

base= 4 inches

Explanation

the area of a parallelogram is given by:

$\text{Area}_{shape}=base\cdot heigth$

then

Let

base= unknown= b

height= 10 in

Area= 40 square inches

replace,

$\begin{gathered} \text{Area}_{shape}=base\cdot heigth \\ 40in^2=b\cdot10in\cdot \\ \text{now, to solve for b, divide both sides by 10 in} \\ \frac{40in^2}{10\text{ in}}=\frac{b\cdot10\text{ in}}{10\text{ in}} \\ 4\text{ in=b} \end{gathered}$

Hence , the base is 4 inches.

I hope this helps you