We need to find the inverse of the funcion:
[tex]f\mleft(x\mright)=x-2/2[/tex]Notice that:
[tex]\frac{2}{2}=1[/tex]Thus, we have:
[tex]f(x)=x-1[/tex]Now, to find its inverse, we can follow the steps below:
• replace x with y;
,• replace f(x) with x;
,• isolate y on the left side;
,• replace y with f⁻¹(x).
We obtain:
[tex]\begin{gathered} x=y-1 \\ \\ y-1=x \\ \\ y-1+1=x+1 \\ \\ y=x+1 \\ \\ f^{-1}(x)=x+1 \end{gathered}[/tex]Now, we need to graph both f(x) and f⁻¹(x).
In order to graph f(x), since it is a line, we can plot two points of the form (x, f(x)) and then join those points to form the line:
[tex]\begin{gathered} f(0)=0-1=-1\text{ point }(0,-1) \\ \\ f(1)=1-1=0\text{ point }(1,0) \end{gathered}[/tex]Similarly, to graph f⁻¹(x), we can do as follows:
[tex]\begin{gathered} f⁻¹\left(0\right)=0+1=1\text{ point }(0,1) \\ \\ f⁻¹\left(1\right)=1+1=2\text{ point }(1,2) \end{gathered}[/tex]Answer:
[tex]f^{-1}(x)=x+1[/tex]