Need help figuring out . suppose it passes through (0,-2) and (9.5,0)

Lets suppose tha the graph passes through points
[tex]\begin{gathered} (x_1,y_1)=(0,-2) \\ \text{and} \\ (x_2,y_2)=(9.5,0) \end{gathered}[/tex]Then, the slope of the dashed line is given by
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-2)}{9.5-0}[/tex]which gives
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{2}{9.5}=0.21052[/tex]Then, we can write
[tex]y=mx+b\Rightarrow y=0.21052x+b[/tex]where the y-intercept can be founded by substituting the first point, that is,
[tex]\begin{gathered} -2=0.21052(0)+b \\ b=-2 \end{gathered}[/tex]Then, the dashed line has equation
[tex]y=0.21052x-2[/tex]Finally, since the values of the red region are above the dashed line then, the inequality which represents the red region is:
[tex]y>0.21052x-2[/tex]