Given the function h(x) = 4x - 3 on the interval 0 ≤ x ≤ 1, we have to find the rate of change of function.
Explanation
[tex]\begin{gathered} h\mleft(0\mright)=4\left(0\right)-3=-3 \\ h\mleft(1\mright)=4\left(1\right)-3=4-3=1 \\ rate\text{ of change=}\frac{h\mleft(x_2\mright)-h\mleft(x_1\mright)}{x_2-x_1}=\frac{1-(-3)}{1-0}=4 \end{gathered}[/tex]Answer: 4
