Respuesta :

[tex]-42=7b^2-385[/tex]

To solve the equation for b:

1. Add 385 in both sides of the equation:

[tex]\begin{gathered} -42+385=7b^2-385+385 \\ 343=7b^2 \end{gathered}[/tex]

2. Divide both sides of the equation into 7:

[tex]\begin{gathered} \frac{343}{7}=\frac{7}{7}b^2 \\ \\ 49=b^2 \end{gathered}[/tex]

3. Find the square root of both terms:

[tex]\begin{gathered} \sqrt[]{49}=\sqrt{b^2} \\ \sqrt[]{49}=b \end{gathered}[/tex]

4. In this case you can write the 49 under the root as:

[tex]\begin{gathered} \sqrt[]{49}=\sqrt[]{(7)^2} \\ \sqrt[]{49}=\sqrt[]{(-7)^2} \\ \\ \sqrt[]{49}=\pm7 \end{gathered}[/tex]

Then, in the given equation b is:

[tex]\begin{gathered} b=7 \\ b=-7 \end{gathered}[/tex]

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