To find the equation which would represent this problem, we have to use two points: (15, 79.6) and (18.4, 84.3).
First, we find the slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{84.3-79.6}{18.4-15}=\frac{4.7}{3.4}\approx1.38[/tex]
Now, we use the slope, one point, and the point-slope formula to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1)_{} \\ y-84.3=1.38(x-18.4) \\ y-84.3=1.38x-25.392 \\ y=1.38x-25.392+84.3 \\ y=1.38x+58.908 \end{gathered}[/tex]
Therefore, an equation that approximates to the given values is y = 1.39x + 58.908.