Question

A boy pulls a 25 kg wagon with a force of 6 N east as another boy pushes it with a force of 4 N east. What is the net force? What is the acceleration?

Answer 1

Using newton's second law:

$\begin{gathered} \Sigma F=F_{\text{net}}=ma \\ where_{} \\ \Sigma F=6N+4N=10N=F_{\text{net}} \\ m=25\operatorname{kg} \\ so\colon \\ 10=25\cdot a \\ solve_{\text{ }}for_{\text{ }}a\colon \\ a=\frac{10}{25} \\ a=\frac{0.4m}{s^2} \end{gathered}$