Question

What is the equation of a circle with center (3, 8) and radius 2?(x + 3)2 + (y + 8)2 = 2(x - 3)2 + (y - 3)2 = 2(x - 3)2 + (y - 8)2 = 4(x + 3)2 + (y + 8)2 = 4

Answer 1

Answer:

(x - 3)² + (y - 8)² = 4

Explanation:

The equation of a circle with center in (h, k) and radius r is equal to:

$(x-h)^2+(y-k)^2=r^2$

Therefore, replacing the center (h, k) by (3, 8) and the radius r by 2, we get:

$\begin{gathered} (x-3)^2+(y-8)^2=2^2 \\ (x-3)^2+(y-8)^2=4 \end{gathered}$

Therefore, the answer is:

(x - 3)² + (y - 8)² = 4