Answer:
Explanation:
Given the equation of the line:
[tex]7x+9y=63[/tex]
To graph the line, first, we determine the intercepts.
When x=0:
[tex]\begin{gathered} 7x+9y=63 \\ 7(0)+9y=63 \\ \begin{equation*} 9y=63 \end{equation*} \\ \frac{9y}{9}=\frac{63}{9} \\ y=7 \end{gathered}[/tex]
The y-intercept is at (0, 7).
When y=0:
[tex]\begin{gathered} \begin{equation*} 7x+9y=63 \end{equation*} \\ 7x+9(0)=63 \\ 7x=63 \\ \frac{7x}{7}=\frac{63}{7} \\ x=9 \end{gathered}[/tex]
The x-intercept is at (9, 0).
Join the points (0, 7) and (9,0) to plot the line as shown below:
