The perimeter of the rectangle below is 198 units. Find the length of side PS.Write your answer without variables.

ANSWER
PS = 47 units
EXPLANATION
We have the perimeter of this rectangle and we have to find the length of the side PS.
The perimeter of a rectangle is the sum of the lengths of the sides or the sum of twice each dimension - this is because the sides have the same length in pairs.
For this rectangle, we have that the perimeter is 198 units,
[tex]2PS+2SR=198[/tex]And sides PS and SR are (4y + 3) and (5y - 3) respectively. Replace into the equation above,
[tex]2(4y+3)+2(5y-3)=198[/tex]We have an equation for y. To solve it first we have to apply the distributive property,
[tex]\begin{gathered} 2\cdot4y+2\cdot3+2\cdot5y-2\cdot3=198 \\ 8y+6+10y-6=198 \end{gathered}[/tex]Then, add like terms,
[tex]\begin{gathered} (8y+10y)+(6-6)=198 \\ 18y=198 \end{gathered}[/tex]And finally, divide both sides by 18,
[tex]\begin{gathered} \frac{18y}{18}=\frac{198}{18} \\ y=11 \end{gathered}[/tex]We now have y = 11, so we can replace it into the expression for the length of side PS,
[tex]PS=4\cdot11+3=44+3=47\text{units}[/tex]The length of the side PS is 47 units.