Question

Evaluate the following $b {}^{2} c {}^{ - 1}$For b=8 and C=-4

Answer 1

We want to evaluate

$b^2c^{-1}$

for b = 8 and c = -4

Solution

From

$\begin{gathered} b^2c^{-1}=b^2\times\frac{1}{c} \\ b^2c^{-1}=\frac{b^2}{c} \end{gathered}$

Put b = 8 and c = -4

$\begin{gathered} b^2c^{-1}=\frac{b^2}{c} \\ b^2c^{-1}=\frac{8^2}{-4} \\ b^2c^{-1}=\frac{64}{-4} \\ b^2c^{-1}=-16 \end{gathered}$

Therefore,

$b^2c^{-1}=-16$