The angles presented on question 2 are vertical angles, which means they are congruent, this means we have the following equation:
[tex]6x+19=7x-2[/tex]
Solving for x:
[tex]\begin{gathered} 6x+19=7x-2 \\ 6x+21=7x \\ 21=x \end{gathered}[/tex]
Making the substitution
[tex]7x-2=7\times21-2=147-2=145[/tex]
Both angles on question 2 measure 145º.
