(Word Problem) Laz had a hard time with his problem on homework. Help him figure out what went wrong in his process. What was his mistake and whats the correct solution.

The triangle given
The value of x and y can be obtained using trigonometric ratio
To get the correct solution:
To get x
[tex]\sin 60=\frac{3}{x}[/tex][tex]x=\frac{3}{\sin 60}=\frac{3}{\frac{\sqrt[]{3}}{2}}=\frac{6}{\sqrt[]{3}}=2\sqrt[]{3}[/tex]To get y
[tex]\begin{gathered} \tan 60=\frac{3}{y} \\ y=\frac{3}{\tan 60} \\ y=\frac{3}{\sqrt[]{3}} \\ y=\sqrt[]{3} \end{gathered}[/tex]The next step is to compare the values of x and y Laz obtained with the correct answer.
Mistake: We can see that Laz did not use the correct trigonometric ratio to solve for x and y.