Question

Need help with homework

Answer 1

I will use the quadratic formula to solve and find the solutions of the equation:

$\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In the case of 4x^2 - 28x + 130:

a = 4

b = -28

c = 130

Thus:

$\frac{-(-28)\pm\sqrt[]{-28^2-4\times4\times130}}{2\times4}$

$\frac{28\pm\sqrt[]{-1296}}{8}$

$\frac{28\pm36i}{8}$

The first solution will be:

$\frac{28+36i}{8}=3.5+4.5i$

The second solution will be:

$\frac{28-36i}{8}=3.5-4.5i$

Answer:

$x=\mleft\lbrace\frac{28+36i}{8},\frac{28-36i}{8}\mright\rbrace$