What is the specific heat of a 54.51 g piece of anunknown metal that exhibits a 45.2°C temperature changeupon absorbing 1870 J of heat?

Respuesta :

Answer:

[tex]0.76\text{ J/g.\degree C }[/tex]

Explanation:

Here, we want to calculate the specific heat capacity of an unknown piece of metal

Mathematically:

[tex]Q\text{ = mc}\Delta T[/tex]

Where:

Q is the quantity of heat which is 1870 J

m is the mass of the piece which is 54.51 g

c is the specific heat capacity that we want to calculate

Delta T is the temperature change which is 45.2

Rewriting the equation in terms of c, we have it that:

[tex]c\text{ = }\frac{Q}{m\Delta T}[/tex]

Substituting the values, we have it that:

[tex]c\text{ = }\frac{1870}{54.51\times45.2}\text{ =0.76 J/g.\degree C }[/tex]

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