[tex]\begin{gathered} \frac{5}{x}+\frac{10x}{24}=\frac{20}{3x} \\ \text{Multiply both sides by x:} \\ 5+\frac{10x^2}{24}=\frac{20}{3} \\ \text{Multiply both sides by 3:} \\ 15+\frac{30x^2}{24}=20 \\ \text{Multiply both sides by 24:} \\ 360+30x^2=480 \\ \text{Subtract 360 from both sides:} \\ 30x^2=120 \\ \text{divide both sides by 30} \\ x^2=\frac{120}{30} \\ x^2=4 \\ \text{take the square root to both sides:} \\ x=\sqrt[]{4} \\ x=\pm2 \end{gathered}[/tex]
Answer:
[tex]c._{\text{ }}x=+2_{\text{ }}or_{\text{ }}-2[/tex]
