How do I plot this And is my answer correct

We are given the following inequality:
[tex]-38\le-6-2x[/tex]To solve for "x" we will add 2x to both sides:
[tex]-38+2x\le-6[/tex]Now we will add 38 to both sides:
[tex]\begin{gathered} 2x\le-6+38 \\ 2x\le32 \end{gathered}[/tex]Now we divide both sides by 2:
[tex]\begin{gathered} x\le\frac{32}{2} \\ \\ x\le16 \end{gathered}[/tex]Therefore, the solution is the values of "x" that are smaller or equal to 16. This can be represented in the real line as follows:
We need to use all the points that are smaller (to the left) than 16. To represent the fact that 16 is also included in the solution we use a point on top of it.
In the case that 16 was not included then we would use a hollowed point on top of it.