Question

Solve for h:A = ¹h (b₁ + b₂)Oh 2A - b₁ + b₂Oh==0 h =2Ab₁+ b₂4bi+by

Answer 1

Given:

There are given the formula:

$A=\frac{1}{2}h(b_1+b_2)$

Explanation:

According to the question:

We need to find the value of h.

So,

First, multiply by 2 on both sides of the equation.

Then,

$\begin{gathered} A=\frac{1}{2}h(b_{1}+b_{2}) \\ 2A=\frac{1}{2}h(b_1+b_2)\times2 \\ 2A=h(b_1+b_2) \end{gathered}$

Then,

$\begin{gathered} 2A=h(b_{1}+b_{2}) \\ h=\frac{2A}{b_1+b_2} \end{gathered}$

Therefore, the value of h is:

$h=\frac{2A}{b_{1}+b_{2}}$

Final answer:

Hence, the correct option is B.