Question

Consider the equation. Now the graph can be completed by drawing the curve through a point on the other side of the vertex. Find the point on the graph of this parabola that has the x-coordinate X = -3

Answer 1

Equation given:

$y=-2(x+4)^2-2$

Procedure:

To find the point on the graph in which x = -3, we have to replace this value in the given equation as follows:

$y=-2((-3)+4)^2-2$

Solving for y:

$y=-2(-3+4)^2-2$$y=-2(1)^2-2$$y=-2-2$

Answer:

$y=-4$

Coordinate: ( -3, -4 )