We have a normal distribution that has a mean of 110 and a standard deviation of 8.
We have to find the z-score for a value of X = 80.
We can use the following expression to find the z-score:
[tex]z=\frac{X-\mu}{\sigma}[/tex]where μ = 110 and σ = 8.
Then, we can solve as:
[tex]z=\frac{X-\mu}{\sigma}=\frac{80-110}{8}=\frac{-30}{8}\approx-3.75[/tex]Answer: z = -3.75
