Question

You randomly select one card from a 52-card deck. Find the probability of selecting a six or a nine.

Answer 1

Given:

• Number if cards in a deck = 52

Let's find the probability of selecting a six or a nine if you randomly select one card from the 52-card deck.

To find the probability, apply the formula:

$P(\text{six or nine)= P(six) + P(nine)}$

Where:

• Number of six's in a deck = 4

,

• Number of nine's in a deck = 4

Thus, we have:

$\begin{gathered} P(six)=\frac{4}{52} \\ \\ P(nine)=\frac{4}{52} \\ \\ P(\text{six or nine)=}\frac{4}{52}+\frac{4}{52} \\ \\ P(\text{six or nine) = }\frac{4+4}{52}=\frac{8}{52}=\frac{2}{13} \end{gathered}$

Therefore, the pprobability of selecting a six or a nine is 2/13.

ANSWER:

$\frac{2}{13}$