Question

Consider the following quadratic equation -x^ 2 equiv-8x+16 Step 1 of 2: Find the values of a, band that should be used in the quadratic formula to determine the solution of the quadratic equation

Answer 1

ANSWER

$\begin{gathered} a=-1 \\ b=8 \\ c=-16 \end{gathered}$

EXPLANATION

Given;

$-x^2=-8x+16$

Subtract 16 from both sides and simplify;

$\begin{gathered} -x^2-16=-8x+16-16 \\ -x^2-16=-8x \end{gathered}$

Add 8x to both sides and simplify;

$\begin{gathered} -x^2-16+8x=-8x+8x \\ -x^2+8x-16=0 \end{gathered}$

Comparing with standard quadratic equation;

$\begin{gathered} -x^2+8x-16=0 \\ ax^2+bx+c=0 \end{gathered}$

Therefore the values of a,b and c are;

$\begin{gathered} a=-1 \\ b=8 \\ c=-16 \end{gathered}$