In △ X Y Z, it's coordinates are X (-3, 1), Y (2, 0) and Z (0, -2). What are the coordinates of the image △ X' Y' Z' after a dilation of 2?I need someone to double check my answer please.

Recall that a dilation by a k factor changes the coordinates in the following way:
[tex](x,y)\rightarrow(kx,ky)\text{.}[/tex]Therefore, the coordinates of triangle X'Y'Z' are:
(-3*2,1*2), (2*2,0*2), and (0*2, -2*2).
Answer: (-6,2), (4,0), and (0,4).