Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
[tex]F\text{ =2}\times10^4\text{ N}[/tex]
The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
[tex]\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}[/tex]
The power of the wind will be
[tex]\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}[/tex]