Given that the initial length of the rod is 80 inches.
And it shrinks 10% when cooled from the furnace.
Let the new length be x inches.
Then the length of the shrinked rod will be
[tex]\begin{gathered} x=[80-10\%\text{ of 80\rbrack inches} \\ x=[80-\frac{10}{100}\times80\text{ \rbrack inches} \\ x=[80-8]\text{ inches} \\ x=72\text{ inches} \end{gathered}[/tex]Hence, the length of the shrinked rod will be 72 inches.