Question

If a model of an airplane is116scale (1 in. = 16 ft), how many inches long would the model be if a certain airplane were 48 ft long?answer in ft

Answer 1

Answer:

3 inches = 0.25 ft

Explanation:

The ratio of inches of the model to feet of the airplane is constant. It means that we can write the following equation:

$\frac{\text{ model}}{\text{ airplane}}=\frac{1\text{ in}}{16\text{ ft}}=\frac{x}{48\text{ ft}}$

Where x is the number of inches of the model. So, solving for x, we get:

$\begin{gathered} \frac{1\text{ in}}{16\text{ ft}}=\frac{x}{48\text{ ft}} \\ \frac{1\text{ in}}{16\text{ ft}}\cdot48ft=\frac{x}{48\text{ ft}}\cdot48\text{ ft} \\ 3\text{ in = x} \end{gathered}$

Therefore, the model of an airplane that is 48 ft long would be 3 in long.

Now, we can convert 3 inches to ft as follows:

$3\text{ in }\times\frac{1\text{ ft}}{12\text{ in}}=0.25\text{ ft}$

Because 1 ft is equivalent to 12 inches.