Question

A student drops a pen from a classroom window on the third floor of the mathematics building. If the pen is dropped from33 ft above ground level, at what velocity does the pen hit the ground? Use - 32 ft/s2 for the acceleration caused by gravity.Ignore air resistance. Round any intermediate calculations to no less than six decimal places, and round your final answer totwo decimal places.

Answer 1

Answer:

45.96 m/s

Explanation:

To find the velocity when the pen hits the ground, we will use the following equation

$v^2_f=v^2_i+2ay$

Where vf is the velocity when the pen hits the ground, vi is the initial velocity, a is the acceleration and y is the height of the building.

So, replacing vi = 0 m/s, a = -32 ft/s², and y = -33 ft, we get

$\begin{gathered} v^2_f=0^2+2(-32)(-33) \\ v^2_f=2112 \\ vf=\sqrt[]{2112} \\ v_f=45.96\text{ m/s} \end{gathered}$

Then, the pen hit the ground at 45.96 m/s