Passing through (-9,-3) and parallel to the line whose equation is y=2x+1What is the equation for the line in point-slope form?

y + 3 = -2(x + 9)
The equation of a line in point-slope form is expressed as;
[tex]y-y_1=m(x-x_1)[/tex]where
• m is the ,slope
,• (x1, y1) is any ,point, on the line
Fro the equation of the line given, the required slope is -2 and the point given is (-9, -3)
Substitute the point and slope into the equation above to have
[tex]\begin{gathered} y-(-3)=-2(x-(-9)) \\ y+3=-2(x+9) \end{gathered}[/tex]Hence the equation for the line in point-slope form is y + 3 = -2(x + 9)