Consider the expenses made by Brianna.
Bicycle for $261.04,
Three bicycle reflectors for $13.07, means $39.21,
A pair of bike gloves for $13.57,
Thus, the total expense till now,
[tex]\text{Expense}=261.04+39.21+13.57=313.82[/tex]Given that Brianna initially had $620, so the amount left after making the above expense is calculated as,
[tex]\text{Amount Left=620-313.82=306.18}[/tex]Given that she plans to spend all or some of this $306.18 to buy outfits which cost $51.03 each. If 'x' is the number of outfits purchased by Brianna then,
[tex]51.03\times x\leq306.18\Rightarrow x\leq\frac{306.18}{51.03}\Rightarrow x\leq6[/tex]Thus, the required inequality for the number of outfiits 'x' is obtained, which has the solution region from negative infinity to 6 . But as we know that the number of outfits cannot be less than zero,
[tex]x\ge0[/tex]Combine both the results. It is observed that the solution region the values of 'x' which are less than 6 but not less than 0, therefore the solution is,
[tex]0\leq x\leq6[/tex]The corresponding diagram is given below,