It is given that
[tex]-4(2x-1)=-6(x+2)-2[/tex]Now let's arrange all the x terms on one side and constant terms on the other.
[tex]\begin{gathered} -4(2x-1)=-6(x+2)-2 \\ -8x+4=-6x-12-2 \\ -8x+6x=-14-4 \\ -2x=-18 \end{gathered}[/tex]Now
[tex]\begin{gathered} -2x=-18 \\ x=\frac{-18}{-2} \\ x=9 \end{gathered}[/tex]So the correct answer is (C