Given:
[tex]\begin{gathered} x=3in \\ y=11in \\ z=5in \\ w=5in \end{gathered}[/tex]
Required:
To find the area of the given figure.
Explanation:
Consider the given figure
Now first we have to calculate the area of the first rectangle.
The formula for area of the rectangle is,
[tex]A1=l\times w[/tex]
Here
[tex]\begin{gathered} l=11in \\ w=3in \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} A1=11\times3 \\ =33in^2 \end{gathered}[/tex]
The area of the second rectangle is,
[tex]A2=l\times w[/tex]
Here,
[tex]\begin{gathered} l=6in \\ w=2in \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} A2=6\times2 \\ =12in^2 \end{gathered}[/tex]
The total area of the given figure is,
[tex]\begin{gathered} A=A1+A2 \\ =33+12 \\ =45in^2 \end{gathered}[/tex]
Final Answer:
The area of the figure is 45 square inches.