Question

In triangles and and def AB equals 4 AC equals 5 bc equals 7 de equals 10 df equals 13 and fe equals 16 . which method could be used to prove the two triangles similar

Answer 1

We know that

$\begin{gathered} AB=4 \\ AC=5 \\ BC=7 \\ DE=10 \\ DF=13 \\ FE=16 \end{gathered}$

Let's make a diagram

First, we have to find the common ratio dividing corresponding sides

$\begin{gathered} \frac{DE}{AB}=\frac{10}{4}=2.5 \\ \frac{DF}{AC}=\frac{13}{5}=2.6 \\ \frac{EF}{BC}=\frac{16}{7}=2.3 \end{gathered}$

As you can observe, neither ratio is equal. If there's no common ratio, then, the triangles are no similar.

Hence, the answer is none.