Respuesta :
For part (a), the mean of the sampling distribution is the same as the population mean. On the other hand, the standard deviation of the distribution is also given.
[tex]\begin{gathered} \mu_{\overline{x}}=20 \\ \sigma_{\overline{x}}=8 \end{gathered}[/tex]For part (b), notice that the sample size, n=64, is greater than 30. Thus, the shape must be a normal distribution. This means that the shape depends on the sample size.
Thus, the answer is option B.
For part (c), substitute the given values into the formula for z.
[tex]\begin{gathered} x=18.7 \\ \mu_{\overline{x}}=20 \\ \sigma_{\overline{x}}=8 \\ \\ z=\frac{x-\mu_{\overline{x}}}{\sigma_{\overline{x}}} \\ =\frac{18.7-20}{8} \end{gathered}[/tex]Simplify the expression.
[tex]\begin{gathered} z=\frac{-1.3}{8} \\ =-0.1625 \end{gathered}[/tex]For part (d), we use the same procedure as part (c).
[tex]\begin{gathered} x=20.6 \\ \mu_{\overline{x}}=20 \\ \sigma_{\overline{x}}=8 \\ \\ z=\frac{x-\mu_{\overline{x}}}{\sigma_{\overline{x}}} \\ =\frac{20.6-20}{8} \end{gathered}[/tex]Simplify the expression.
[tex]\begin{gathered} z=\frac{0.6}{8} \\ =0.075 \end{gathered}[/tex]For part (e), to obtain the given probability, we must first find the z-score and then check the z-score table for the probability. Since we obtain the value earlier which is -0.1625, look for the value in the z-score table.
Notice that we don't have the exact value for -0.1625. We only have values for -0.16 and -0.17. Thus, we use the interpolation.
[tex]\begin{gathered} P(x<18.7)=P(z\le-0.16)-\frac{25}{100}\lbrack P(Z\le-0.16)-P(Z\le-0.17)\rbrack \\ =0.43640-\frac{25}{100}(0.43640-43251) \\ =0.43640-\frac{25}{100}(0.00389) \\ =0.43640-0.0009725 \\ =0.4354275 \\ \approx0.4354 \end{gathered}[/tex]For part (f), since we already have the value for the z-score, look at the z-score table for the probability for the z-score which is less than or equal to 0.075.
Notice that we also do not have the exact value for 0.075. Thus, use the same procedure as part (e).
[tex]\begin{gathered} P(x\le20.6)=P(z\le0.07)+\frac{5}{10}\lbrack P(Z\le0.08)-P(Z\le0.07)\rbrack \\ =0.52790+\frac{5}{10}(0.53188-0.52790) \\ =0.52790+\frac{5}{10}(0.00398) \\ =0.52790+0.00199 \\ =0.52989 \\ \approx0.5299 \end{gathered}[/tex]

