Given data
*The given spring constant is k = 55 N/m
*The given force is F = 2000 N
The expression for the stretching of the band is given by Hooke's law as
[tex]\begin{gathered} F=kx \\ x=\frac{F}{k} \end{gathered}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} x=\frac{2000}{55} \\ =36.3\text{ m} \end{gathered}[/tex]Hence, the stretching of the band is x = 36.3 m