Question

.Height has been rounded for computational ease.If X = 3 units, Y = 3 units, and Z = 6 units, then what is the surface area of the right triangular pyramid shown above

Answer 1

Solution:

The surface area of the pyramid will be calculated below as

$\begin{gathered} A_s=\frac{1}{2}xy+\frac{3}{2}xz \\ x=3,y=3,z=6 \end{gathered}$

By substituting the values, we will have

$\begin{gathered} A_{s}=\frac{1}{2}xy+\frac{3}{2}xz \\ A_s=\frac{1}{2}\times3\times3+\frac{3}{2}\times3\times6 \\ A_s=\frac{9}{2}+27 \\ A_s=\frac{9+54}{2} \\ A_s=\frac{63}{2} \\ A_s=31.5unit^2 \end{gathered}$

Hence,

The final answer is

$\Rightarrow31.5units^2$