Question

Find the zeros of the function: F(x)=3x^2-16x+21

Answer 1

We will have the following:

We will determine the zeros as follows:

$\begin{gathered} 3x^2-16x+21=0\Rightarrow x=\frac{-(-16)\pm\sqrt{(-16)^2-4(3)(21)}}{2(3)} \\ \\ \Rightarrow x=\frac{7}{3} \\ \\ and \\ \\ \Rightarrow x=3 \end{gathered}$

So, the zeros are located at x = 7/3 and x = 3.