Question

Question 4 of 10Select the two values of x that are roots of this equation.x2 – 5x + 3 = 0OA. x=5+4675 37X=2B. X=5- 3725 - 13C. X =2<-5-

Answer 1

ANSWER :

The roots are C and D.

EXPLANATION :

From the problem, we have :

$x^2-5x+3=0$

Using quadratic formula with a = 1, b = -5 and c = 3

$\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ x=\frac{-(-5)\pm\sqrt{(-5)^2-4(1)(3)}}{2(1)} \\ \\ x=\frac{5\pm\sqrt{25-12}}{2} \\ \\ x=\frac{5\pm\sqrt{13}}{2} \end{gathered}$