May please get help with a and c?I have tried multiple times to get the corrects for them but still couldn’t.

To answer this question, we need to remember that the sum of the internal angles of a triangle is equal to 180°. We have two triangles, and we need to find the measure for one of the angles of each of them.
Then we have:
We have that:
[tex]m\angle A+m\angle B+m\angle C=180^{\circ}[/tex]Then
[tex]\begin{gathered} m\angle A=42^{\circ} \\ m\angle B=48^{\circ} \\ 42^{\circ}+48^{\circ}+m\angle C=180^{\circ} \\ 90^{\circ_{}}+m\angle C=180^{\circ} \end{gathered}[/tex]Now, to solve the equation, we have to subtract 90° from both sides of the equation:
[tex]\begin{gathered} 90^{\circ}-90^{\circ}+m\angle C=180^{\circ}-90^{\circ} \\ m\angle C=90^{\circ} \end{gathered}[/tex]Therefore, m
We can proceed similarly in this case. Then we have:
[tex]\begin{gathered} m\angle D+m\angle E+m\angle F=180^{\circ} \\ m\angle D=29^{\circ},m\angle E=47^{\circ} \\ 29^{\circ}+47^{\circ}+m\angle F=180^{\circ} \\ 76^{\circ}+m\angle F=180^{\circ} \end{gathered}[/tex]Finally, we can subtract 76 degrees from both sides of the equation:
[tex]\begin{gathered} 76^{\circ}-76^{\circ}+m\angle F=180^{\circ}-76^{\circ} \\ m\angle F=104^{\circ} \end{gathered}[/tex]Therefore, the measure of the angle F is equal to 104 degrees, m.
In summary, we have that:
[tex]\begin{gathered} m\angle C=90^{\circ} \\ m\angle F=104^{\circ} \end{gathered}[/tex]