them Explanation
To find the linear equation, we pick two points and insert into the equation below;
[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \text{where x}_1=0;y_1=-3_{} \\ x_2=6,y_2=0 \end{gathered}[/tex][tex]\begin{gathered} y-(-3)=\frac{0-(-3)}{6-0}(x-6) \\ y+3=\frac{3}{6}(x-0) \\ y+3=\frac{x}{2} \\ 2y+6=x \\ 2y-x=-6 \end{gathered}[/tex]
Answer:
[tex]2y-x=-6[/tex]
