you roll a six-sided die two times what is the probability of rolling an odd number and then rolling an odd number

Given,
The number of sides in the cube is 6.
The numbered value in the cube is 1, 2, 3,4, 5, 6.
Required:
The probability of rolling an odd number and then rolling an odd number.
The probability of getting odd number number on first roll is,
[tex]\begin{gathered} P(odd)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]The probability of getting odd number number on second roll is,
[tex]\begin{gathered} P(odd)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]The probability of getting odd than odd,
[tex]\begin{gathered} P=\frac{1}{2}\times\frac{1}{2} \\ =0.5\times0.5 \\ =0.25 \\ =25\text{ \%} \end{gathered}[/tex]Hence, the probability of rolling an odd number and then rolling an odd number is 25%.