Respuesta :

Given,

The number of sides in the cube is 6.

The numbered value in the cube is 1, 2, 3,4, 5, 6.

Required:

The probability of rolling an odd number and then rolling an odd number.

The probability of getting odd number number on first roll is,

[tex]\begin{gathered} P(odd)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]

The probability of getting odd number number on second roll is,

[tex]\begin{gathered} P(odd)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]

The probability of getting odd than odd,

[tex]\begin{gathered} P=\frac{1}{2}\times\frac{1}{2} \\ =0.5\times0.5 \\ =0.25 \\ =25\text{ \%} \end{gathered}[/tex]

Hence, the probability of rolling an odd number and then rolling an odd number ​is 25%.

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