Ok, the probability of rolling either a 2 or a 3 on a fair six-sided number cube is equivalent to divide the options that we need over the total number of options, let's do it:
[tex]P(2\text{ or 3)=}\frac{2}{6}=\frac{1}{3}[/tex]The probability is 1/3 or 33.3% aproximately.
