Question

What was the total amount of water in the tank before it was drained

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

Table

Step 02:

We must analyze the data table to find the solution.

constant rate:

$m\text{ = }\frac{y2-y1}{x2-x1}=\frac{330-450}{30-10}=\frac{-120}{20}=-6$

y = mx + b

(y - y1) = m (x - x1)

(y - 450) = -6 (x - 10)

y = -6x + 60 + 450

y = -6x + 510

if x = 0 (initial time)

y = -6*(0) + 510

y = 0 + 510

y = 510

The answer is:

510 gallons