Question

Solving Equatic Equations:4x²+x-3=0

Answer 1

S={-1,3/4}

1) Let's solve this quadratic equation

4x²+x -3=0

Let's solve that using the traditional way. Applying the Resolutive Formula for Quadratic Equations. First, we find the discriminant Delta:

$\begin{gathered} \Delta=\text{ 1²-4(4)(-3) }=1\text{ +}48=\text{ 49} \\ x\text{ =}\frac{-b+-\sqrt[]{49}}{2a} \\ x_1=\frac{-1+7}{8}=\frac{3}{4} \\ x_2=\frac{-1-7}{8}=-1 \end{gathered}$

2) So the Solution set is S={-1, 3/4} the roots for that quadratic equation, where y=0 at x=-1, and x=3/4