To solve this problem, we will use the formula for monthly compounded interest:
[tex]T=P(1+\frac{r}{12})^{12t},_{}[/tex]where:
- T is the final amount,
- P is the initial amount,
- r is the annual interest rate,
- t is the number of years.
Substituting T=3000, t=15, and r=0.08, we get:
[tex]3000=P(1+\frac{0.08}{12})^{12\times15}.[/tex]Solving the above equation for P we get:
[tex]P=\frac{3000}{(1+\frac{0.08}{12})^{12\times15}}=907.19.[/tex]Answer:
[tex]907.19[/tex]dollars.