Given the equation:
[tex]x^2-36=0[/tex]
Let's find all the solutions of the equation.
To find the solution, let's solve the equation for x.
The first step is to add 36 to both sides of the equation:
[tex]\begin{gathered} x^2-36+36=0+36 \\ \\ x^2=36 \end{gathered}[/tex]
Take the square root of both sides of the equation:
[tex]\begin{gathered} \sqrt{x}=\pm\sqrt{36} \\ \\ x=-\sqrt{36},\text{ }\sqrt{36} \\ \\ x=-6,\text{ 6} \end{gathered}[/tex]
Therefore, the solutions in trigonometric form are:
[tex]-\sqrt{36},\text{ }\sqrt{36}[/tex]
ANSWER:
[tex]x=-6,\text{ 6}[/tex]
