I need help with this Geometry HWI need to find the surface area

the surface are is the sum of all areas of the pyramid
so
Lateral triangle
the area is
[tex]\begin{gathered} A=\frac{b\times h}{2} \\ \\ A=\frac{4\times11.1}{2} \\ \\ A=22.2 \end{gathered}[/tex]This triangle is repeated 3 times since it makes all the faces except the lower one
Low triangle
[tex]\begin{gathered} A=\frac{b\times h}{2} \\ \\ A=\frac{4\times3.5}{2} \\ \\ A=7 \end{gathered}[/tex]Total surface Area
we add each area of each face of the pyramid
so
[tex]\begin{gathered} A=22.2+22.2+22.2+7 \\ A=73.6 \end{gathered}[/tex]Then the surface Are is 73.6 square meters