Explanation:
Given the sequence: 18, 22, 26, 30
[tex]\begin{gathered} We\text{ are asked to write it in the form:} \\ a_{n\text{ }}=\text{ c + \lparen n-1\rparen d} \\ c\text{ = first term = 18} \\ d\text{ is the common difference between terms.} \\ T3\text{ - T2 = 26 -22 = 4 = d} \\ a_{n\text{ }}=\text{ 18 + \lparen n-1\rparen4} \end{gathered}[/tex]
Answer: an = 18 + (n-1)4
an = 4n + 14
