Since it is a right triangle, then you can use the trigonometric ratio
[tex]\tan (\theta)=\frac{\text{opposite leg}}{\text{ adjacent leg}}[/tex]
So, in this case, you have
[tex]\begin{gathered} \theta=29\text{ \degree} \\ \text{ adjacent leg = 16} \\ \text{ opposite leg = x} \end{gathered}[/tex]
Applying the trigonometric ratio
[tex]\begin{gathered} \tan (29)=\frac{x}{16} \\ \text{ Multiply by 16 on both sides of the equation} \\ \tan (29)\cdot16=\frac{x}{16}\cdot16 \\ \tan (29)\cdot16=x \\ 8.87=x \end{gathered}[/tex]
