Question

write the equation of the circle centered at (6, 3) with radius 6

Answer 1

Answer:

$(x-6)^2+(y-3)^2=36$

Explanation:

If the equation of a circle is given by

$(x-a)^2+(y-b)^2=r^2$

then the circle is centred at (a, b) and the radius is r.

Now in our case, we know that (a, b) = (6, 3) and r = 6; therefore, the above equation gives

$(x-6)^2+(y-3)^2=6^2$

which can also be written as

$\boxed{\left(x-6\right)^2+\left(y-3\right)^2=36.}$

which is our answer!